B How long to travel 150m at 26m/s with an acceleration of -2.5m/s^2?

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To determine how long it takes to travel 150 meters at a speed of 26 m/s with a deceleration of -2.5 m/s², one must first calculate the stopping distance. The stopping distance can be found using the formula d = v² / (2a), which results in a distance of 169 meters, indicating that the vehicle will not stop in time to avoid hitting the child. The time to stop can be calculated using the formula t = v/a, yielding a time of 10.4 seconds to come to a complete stop. Since the stopping distance exceeds 150 meters, the vehicle will still be moving when it reaches the child. Therefore, the driver has no time to avoid the collision.
Erin Pashanov
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Driving along a steady speed of 26m/s and suddenly see a child 150m from you. Breaks can produce acceleration of -2.5m/s^2 but it takes time to get the foot from the gas to the brake pedal. How much time do you have, if to avoid hitting the child?
 
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What distance to come to a stop?
How much of the 150 m is left?
How long to travel that distance?
 
bhillyard said:
What distance to come to a stop?
How much of the 150 m is left?
How long to travel that distance?
I guess it is how long to travel the distance. I copied the exact question I got.
 

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