How long will it take the rabbit to come to a momentary complete stop

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Homework Help Overview

The discussion revolves around determining the time it takes for a rabbit to come to a complete stop, using provided equations related to its motion. The subject area includes kinematics and motion equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use kinematic equations to find the stopping time, while some participants seek clarification on the initial problem context and the significance of the time difference noted.

Discussion Status

Participants are engaging in clarifying the problem details and discussing the validity of the original poster's calculations. There is no explicit consensus on the interpretation of the time difference mentioned.

Contextual Notes

There is a request for additional details about the initial question, indicating that some information may be missing or unclear. The discussion also touches on the significance of a small time difference in the context of the overall travel time.

mcohen519
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Homework Statement



Using the equations from question 1 determine how long it will take the rabbit to come to a complete momentary stop.

Homework Equations



X= 30cm + (-40 cm/s)t + (24 cm/s^2)t^2

V= (-40cm/s) + (12 cm/s^2)t

V^2= (-40 cm/2)^2 + 2(12 cm/s^2)[X-30cm]

The Attempt at a Solution



I have attempted to work this using the middle equation and come up with an answer of 3.33 seconds for the rabbit to stop. However, the entire length of travel of the rabbit is 3.4 sec. Need help finding what I am missing. thanks
 
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Can you give some more details about what the first question was? Like numbers and stuff
 
The answer you have is correct. But what do you mean by "the entire length of travel"?
 
The entire graph spans from 0 to around 3.4 seconds of travel time.
 
Hmm, weird. But it is a difference of 0,07. Are you sure it's significant?
 

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