How Much Dissolved Substance Remains After Boiling?

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After boiling a 200mL solution with 1g/L of a solid, the remaining volume is 136mL. The key question is whether the amount of dissolved solid changes after boiling. The initial concentration is 0.2g of solid in 200mL, and since boiling only removes water, the amount of dissolved solid remains the same at 0.2g. Thus, the dissolved substance does not decrease, only the volume of the solvent does. The focus should be on the amount of solid remaining, which is unchanged despite the reduction in volume.
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Homework Statement


A solution 200mL solution has 1g/L of a solid dissolved in it. After boiling, there is only 136mL remaining. How much of the dissolved substance is left?

I figured that if
C1V1=C2V2, then if the concentrations were equal after calculation, i could the concentration after from the concentration before so that
C2=(C1V1)/V2 thus converting the concentration to grams afterwards and subtracted that value from the previous one.
 
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IMHO you are misinterpreting the question. You are not asked about a new concentration, but whether amount of dissolve solid changed.

Did it? What was removed from the solution?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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