How Much Energy Does a Refrigerator Use in a Single Day?

AI Thread Summary
The discussion focuses on calculating the daily energy consumption of a freezer advertised at 457 kWh per year. To find the daily usage, participants clarify that the annual rate should be divided by 365 days, resulting in approximately 1.25 kWh per day. There is confusion regarding unit conversions, particularly between kilowatt-hours and joules, with clarification that 1 kWh equals 3.6 million joules. Participants assist each other in understanding the calculations and conversions necessary for the problem. Overall, the thread emphasizes the importance of accurate unit conversion in energy calculations.
fiziks09
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Homework Statement


A freezer has a coefficient of performance of 6.30. It is advertised as using electricity at a rate of 457kWh/yr.
a)On average how much energy does it use in a single day?
b) What maximum mass of water at 20.0 degree celsius could the freezer freeze in a single day.

NOTE: One kilowatt hour is an amount of energy equal to running a 1-kW appliance for one hour


Homework Equations


COP = Q / W


The Attempt at a Solution


I tried to use comparison like so;

if 457kWh is the rate for 365 days
then xkWh is the rate for 1 day

This gives me 1.25 J which is very wrong.

Please can i get clues on how to start or what to do on the "A" part of the question. It's really twisting my head..thanks a lot for your help..
 
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Hi fiziks09! :smile:

What you have is 1.25 kWh, which is 1250 Watt times 1 hour.
This is not 1.25 J, which is 1.25 Watt times 1 second.

You'll need to convert the unit...
 
okay..
but converting the unit still gives a wrong answer...
 
How did you convert it?
 
okay i might have misunderstood. I'm so sorry..what conversion is being made?
is it from kWh to Joules or what? if so how so??
 
Allright i got it now..
since 1kWh = 3.6MJ (which is 3600000J)

1.25kWh X 36000000 = 4.5 X 10^6 Joules..

thanks for the help...
 
Good! :smile:
 
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