How Much Force Stopped the Diver Underwater?

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To determine the force that stopped a 50 kg diver underwater, the correct approach involves calculating the acceleration using the equation v² - u² = 2ad, where the initial velocity (u) is 4 m/s, the final velocity (v) is 0, and the distance (d) is 3 meters. The acceleration is not equal to -9.8 m/s², as it must account for the diver's motion through the water. Once the acceleration is found, it can be applied in the formula F = ma to calculate the net force. This method provides a more accurate representation of the forces acting on the diver as he comes to a stop.
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Homework Statement


A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?

Homework Equations


Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?

The Attempt at a Solution


i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.
 
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plqaokws said:

Homework Statement


A 50 kg diver enters the water moving at 4 m/s. He eventually comes to a stop 3 meters below the water surface. What amount force brought the diver to a stop?


Homework Equations


Is the acceleration -9.8 m/s^2?
Then, would you use F = ma to find the net force?


The Attempt at a Solution


i tried to do F = (50 kg)(-9.8 m/s^2) but i don't think that's right...

Thank you.

This will not work as the acc is not equal to -g. You have the velocity when the body touches the water surface. This is the initial velocity. Now the final velocity is zero.And the distance is 3m. So by v^2-u^2=2ad.You can find a, and then you can apply f=ma.Here v is the final velocity and u is the initial velocity.
 
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