How much heat is converted into work?

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In the discussion, a Carnot engine is analyzed with 5000 joules of heat input, where the hot and cold reservoir temperatures are 500 K and 250 K, respectively. The maximum efficiency of the engine is calculated using the Carnot efficiency formula, resulting in only 2500 joules being converted into work. The second part of the discussion involves calculating work done along a path on a pressure-volume graph, where participants express difficulty identifying points on the graph. The work done in a gas system is determined by the area under the curve on the graph between specified points. Understanding these principles is crucial for accurately calculating work and efficiency in thermodynamic systems.
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1) Five thousand joules of heat is put into a Carnot engine whose hot and cold reservoirs have temperatures of 500 and 250 K, respectively. How much heat is converted into work?

here's what i did...
i know that... QC / QH = TC / TH
W = 5000, Tc = 250, Th = 500, Qh = ?, Qc = ?

first I found Qh , which = (eCarnot = W/Qh) ----- and solve for Qh and get (Qh = W/eCarnot) ------eCarnot also equals [1-(Tc/Th)] = [1-( 250 / 500 ) ] = 0.5
so Qh = W / [1-(Tc/Th) = 5000 / 0.5 = 10000
after I got Qh I used the equation (Qc = Qh - W) to solve for Qc and this should be the answer...
Qc = Qh - W = 10000-5000 = 5000 , so Qc = 5000 ...but it still wrong :cry:



2) The pressure and volume of a gas are changed along a path ABCA in the figure. The vertical divisions on the graph represent 4.5 105 Pa, and the horizontal divisions represent 4.0 10-3 m3. Determine the work done (including algebraic sign) in each segment of the path.

cj6_p15-10alt.gif


a ) A to B = ? J
b ) B to C = ? J
c ) C to A = ? J

This question..i know that W= P ( Vf-Vi )
but i still can't locate the dots on the graph! :confused:
 
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For question one the maximum efficencey of a carnot engine is given by;

1 - \frac{T_{C}}{T_{H}}

This will give you a fraction. This in the fraction of the energy which can be used (i.e. work done). So all you need to do is multiply the input energy (Q_{H}) by this fractional efficency.

-Hoot:smile:
 
iceT said:
1) Five thousand joules of heat is put into a Carnot engine whose hot and cold reservoirs have temperatures of 500 and 250 K, respectively. How much heat is converted into work?
The 5000 J. of heat represents Qh not W.

W = .5 Qh = 2500 J.

So only 2500 J of the 5000 is converted into work.


2) The pressure and volume of a gas are changed along a path ABCA in the figure. The vertical divisions on the graph represent 4.5 105 Pa, and the horizontal divisions represent 4.0 10-3 m3. Determine the work done (including algebraic sign) in each segment of the path.

a ) A to B = ? J
b ) B to C = ? J
c ) C to A = ? J

This question..i know that W= P ( Vf-Vi )
but i still can't locate the dots on the graph! :confused:
The work done is the area under the graph between those points.

AM
 
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