How much is it lengthened from its untensioned length of 30.2 cm?

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A nylon tennis string under a tension of 245 N and with a diameter of 0.92 mm is analyzed to determine its elongation from an untensioned length of 30.2 cm. The relevant formula involves Young's modulus, which for nylon is approximately 5e9 Pa. The calculation shows that the string lengthens by 6.1e-8 cm when the proper units are applied. It's crucial to convert measurements to meters and calculate the cross-sectional area using the diameter. Understanding these conversions and the application of the formula is essential for accurate results.
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Homework Statement



A nylon tennis string on a racket is under a tension of 245 N. If its diameter is 0.92 mm, by how much is it lengthened from its untensioned length of 30.2 cm?

Homework Equations



F=E(delta L/L initial)A

The Attempt at a Solution



245N=(5e9)(?/30.2)(.0266)

delta L = 6.1e-8cm
 
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You know the stress, to find the strain you need to know Young's modulus for Nylon.
That is the ratio of the stress to the strain ( can't remember which way round )
 
elastic modulus for nylon is 5e9
 
that seems right. does that not match with the answer? Its been a while since i used that equation
 
So you'll want to convert the diameter and the "untensioned length" to meters. Also, you want to think of the cross sectional area as the area of a circle, which you know the diameter of. Does that help?
 
oh you it has to be in meters. and mm is 1x 10^-3 meters.
 

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