How much light passes through a window?

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A lamp emitting 1600 lumens is positioned 16 inches from a window measuring 0.015m². The discussion centers on calculating the amount of light passing through the window, considering the lamp's isotropic nature. It is suggested that the light intensity (lux) can be determined by the formula lux = lumens/m², and the light through the window can be calculated using the area ratio of the window to the total area affected by the lamp's light. Clarification is sought on whether to treat the light source as isotropic or to consider the wall's influence. Ultimately, the consensus is to treat the light as emanating from a sphere for accurate calculations.
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Homework Statement


A lamp producing 1600 lumens is 16" away from a window of 0.015m^2 on a wall 0.14m^2, what is the amount of light through the window.


Homework Equations


lux = lumens/m^2


The Attempt at a Solution


Since there's no material in the window, shouldn't it be the full 1600 lumens seen inside?
 
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bobobano said:

Homework Statement


A lamp producing 1600 lumens is 16" away from a window of 0.015m^2 on a wall 0.14m^2, what is the amount of light through the window.


Homework Equations


lux = lumens/m^2


The Attempt at a Solution


Since there's no material in the window, shouldn't it be the full 1600 lumens seen inside?

Welcome to the PF.

I think the point of the question is that the light source is isotropic, so only a fraction of the total light goes through the area of the window. How can you calculate the fraction of the total area that the window represents (hint -- use the distance to the window for something...)
 
am I correct in thinking that if I multiply the lux over the area, from the lamp to the window, by the window's area I'll get the lumens through the window?

Light through window = (light from lamp)/(pi*distance2)*(window surface area)
 
bobobano said:
am I correct in thinking that if I multiply the lux over the area, from the lamp to the window, by the window's area I'll get the lumens through the window?

Light through window = (light from lamp)/(pi*distance2)*(window surface area)

It is some area ratio, but on re-reading the question, maybe the light source is not isotropic? They mention a wall and a window, so I'm not sure whether to ratio the area of the window to the wall or to an isotropic sphere. Is there a picture that goes with the question, or else are you able to understand the question well enough to answer it now?
 
I dropped him an e-mail and he says to consider it as a sphere.
 
bobobano said:
I dropped him an e-mail and he says to consider it as a sphere.

Okay, so you know what to ratio then?
 
yea.
 
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