How Much Voltage Is Needed to Suspend Charged Water Droplets?

AI Thread Summary
To suspend charged water droplets in mid-air, the electric force must balance the gravitational force acting on them. The relevant equations include the electric field strength (E) and the relationship between voltage (V), electric field, and distance (d). The electric field between two horizontal metal plates can be calculated, and it is essential to consider the mass of the droplets in the calculations. The discussion highlights the importance of correctly identifying the variables and equations needed for the problem. Ultimately, the participants successfully resolved the issue with guidance from others.
Chawker
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Homework Statement


You intend to suspend water droplets in mid-air to understand rainfall.

You give the droplets a small positive charge, and keep them suspended by an electric field upwards.

The experiment consists of two horizontal metal plates, separated by 9.3m. The water droplets have a mass of 2.8 * 10^-9 kg and have a charge of 6.4*10^-10 C

What voltage should you supply to keep them hovering?

Homework Equations



V = E/d
E=kq/r^2[/B]

The Attempt at a Solution



Kind of lost on this one. I thought about using e=kq/r^2 with the given information then substituting it into the first equation however that still doesn't include the mass component of the question, even if its needed at all.

How should i go about this problem?
 
Last edited:
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Hello Chawker, :welcome:

Chawker said:
V = e/d
In turn, I am lost on this one. You could have avoided that by listing your variable names in part 1 (e = electric field strength ? In physics e is electron charge) Then your eqn doesn't fly dimensonally at all. Where does it come from ?

Chawker said:
seperated by 9.3m
big experiment ?

Your elevant equations set is incomplete: they do not feature the mass at all.
 
For drops to hover the Electric force ##F = Eq ## must balance the gravitational force ## F=mg ##. What is the E field?

Edit: ##E = \frac{Kq}{r^2} ## is for point charges. What kind of Electric field is there between two charged plates ?
 
Chawker said:
two horizontal metal plates
form a capacitor
 
PumpkinCougar95 said:
For drops to hover the Electric force ##F = Eq ## must balance the gravitational force ## F=mg ##. What is the E field?

Edit: ##E = \frac{Kq}{r^2} ## is for point charges. What kind of Electric field is there between two charged plates ?

So we're looking at Eq = mg then solving v = E *d?

EDIT : Figured it out, thanks for the help guys!
 
You're welcome
 
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