How Much Work Is Needed to Move a Charge in an Electric Field?

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The discussion focuses on calculating the work required to move a point charge q2 = 5.60μC from (0.180 m, 0) to (0, 0.370 m) in the electric field created by another fixed point charge q1 = 2.30μC. The key insight is that the electric force is conservative, allowing the use of potential energy differences to determine work. The formula W = -ΔPE is essential, emphasizing that work depends solely on the initial and final positions, not the path taken. Additionally, the distinction between constant and variable forces is highlighted, necessitating integration for variable forces.

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A positive point charge q1 = 2.30uC is located at the origin (x=0, y=0). The charge is held fixed. Another point charge q2 = 5.60uC starts at the point (0.180 m,0). What is the magnitude of the work required to move q2 to
(0,0.370 m) (in J)?

How do I do this?

I know W =Fd, but I don't think I can use the equation F = (k1q2)/r^2, because the distance is constantly changing.

Can anyone at least give me a hint or some insight?
 
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Remember, the electric force is conservative. That means that the path traveled does NOT affect the total work done. It's simply a matter of where the point starts, and where it ends. Find the potential energy at each place, and W = -\Delta PE.

Note that work is only done when r changes, by the way. Otherwise, the charge is traveling on an equipotential surface, and you get to move it around for free.

Also, W = F DOT d, which is an important distinction.
 
Indeed, W=Fd holds only if F is constant. If F changes over the distance, you have to cut the distance into many small pieces and take F to be constant over each piece and sum up the contributions. In other words: integrate.
 

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