How much work is required to lift a 10m chain with 80kg from one end to 6ft?

[imranq]

Homework Statement

You have a chain of length 10m with 80kg, how much work does it take to lift this chain from one end to 6ft?

Homework Equations

\delta = \frac{10}{80} = .125

The Attempt at a Solution

W = \int{F(x)}\,dx = \int^{6}_{0}{\delta lg}\,dl = \frac{\delta l^2g}{2}

I don't think that is right though

 

[Redbelly98]

So far so good, you just need to evaluate the integrated expression at the integral's limits.

Is it 6 ft or 6 m?

 

[imranq]

Oh whoops! Everything that denotes length is in feet

 

[Redbelly98]

Okay. I'm wondering about the "kg" too then.

 

[imranq]

I don't really remember the problem so well. But the inherent integral should be the same, no? Unless you refer to lbs as weight or something.

 

[Redbelly98]

Yes, the inherent integral is the same. Using lbs can get a little confusing since lbs are a force unit, not mass.