How Strong Does a Fishing Line Need to Be to Stop a Drifting Salmon?

  • Thread starter Thread starter Kawasaki268F
  • Start date Start date
  • Tags Tags
    Line Strenght
AI Thread Summary
To determine the minimum strength of a fishing line needed to stop a drifting salmon weighing 78 N over a distance of 13 cm, constant acceleration equations must be applied. The initial horizontal velocity of the salmon is 3.1 m/s, and the problem involves calculating the necessary deceleration to bring the fish to a stop. Using the equation Vf^2 = V0^2 + 2a(x - x0) along with F = ma, the required force can be derived. The tension in the line must match or exceed this force to effectively stop the salmon. Accurate calculations are essential to ensure the fishing line can withstand the required strength.
Kawasaki268F
Messages
9
Reaction score
0

Homework Statement


The tension at which a fishing line snaps is commonly called the line's “strength.” What minimum strength is needed for a line that is to stop a salmon of weight 78 N in 13 cm if the fish is initially drifting horizontally at 3.1 m/s? Assume a constant deceleration.


Homework Equations


I need to use constant acceleration equations...so: v=V0+at, x-x0=v0t+(1/2)at^2...there are 3 other equations for constant acceleration but I don't think i have learned them yet.

The Attempt at a Solution


I am pretty stuck on this one as I have no idea which equation to use and what to do after that to find the solution
 
Physics news on Phys.org
I got it with the help of a friend using Vf^2=V0^2+2a(x-x0) and F=ma
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top