How to approach a simple harmonic motion problem

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To solve the simple harmonic motion problem, the angular frequency (ω) can be calculated using the formula ω = √(k/m), where k is the spring constant and m is the mass. For a spring constant of 0.50 N/m and a mass of 0.7 kg, ω is determined to be 0.845 rad/s. The confusion arose regarding the distinction between angular frequency and frequency, with the latter being ω/2π. The correct angular frequency is confirmed as 0.845 rad/s, clarifying the initial misunderstanding. This discussion highlights the importance of correctly applying formulas in physics problems.
hughes
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This is the question:

A massless spring with a spring constant of 0.50 N/m, has a mass of 0.7 kg on its end. The maximum speed of the end is 2.5 m/s. What is the angular frequency of the system?

I don't know how to approach this problem at all. I just know that omega/2pi is the frequency. But, we don't even have omega. I am so stuck and confused.
 
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Can you write an equation for the motion of the spring.

Doesn't ω depend only on spring constant, k, and mass, m, both of which you know?
 
i see, i forgot omega is the sqrt of k/m. thanks for the reply.
 
ω is equal to .845 m/s. Divide that by 2pi to get the angular frequency and you get .1345, which is incorrect.

Edit: Angular frequency (not frequency) is .845 m/s (the answer).

Thanks for the help. I really do appreciate it.
 
Glad to help !
 
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