How to arrive at answer for integration question

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To solve the integration question regarding a stone thrown upwards with an initial velocity of 20 m/s and accelerated downwards by gravity at 10 m/s², the antiderivative of the acceleration must be calculated. The correct approach involves integrating the acceleration function, which is -10 m/s², leading to the equation v(t) = -10t + C. The integration process does not require including units in the integral. Clarification on the signs and units is essential for arriving at the correct solution. Understanding these concepts allows for progress in solving the problem.
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Firstly, I am sorry if this is the wrong section (I really didn't know what each section meant, but I posted here since I am beginner)

Homework Statement



A stone is thrown up into the air at 20m/s is accelerated constantly downwards by gravity at about 10m/s2

Find the anti derivative of the acceleration

Note: I am not solving for C

Homework Equations


The Attempt at a Solution



The antiderivative of 20m/s is 10m/s2
and the antiderivate of -10m/s is -5m/s2

Neither of those match up to the answer, so I'm not sure how to arrive at the answer.

The answer in the book is v= -10t + c

Thankyou
 
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If you have a = 10 then you need to find \int 10\ dt. There's no need to include units in your integral.
 
Ah, thank you very much. Can finally get on with work! =)
 
JHamm said:
If you have a = 10 then you need to find \int 10\ dt. There's no need to include units in your integral.
That should be a = -10. Of course, the units are m/s2 .
 
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