How to Calculate Distance and Velocity in a Police Chase Scenario?

  • Thread starter Thread starter Rker
  • Start date Start date
Click For Summary
SUMMARY

This discussion focuses on calculating the distance and velocity of a police car pursuing a speeding vehicle in a school zone scenario. The speeding car travels at 80 km/hr, while the police car accelerates from rest at 8 m/sec² after a 0.5-second reaction time. The key equations involve setting the distance traveled by both vehicles equal to each other to solve for time (T) and subsequently determining the distance and speed of the police car when it catches up to the speeder. The quadratic formula is utilized to find the positive value of T, confirming the setup is correct.

PREREQUISITES
  • Understanding of kinematic equations for uniformly accelerated motion
  • Familiarity with converting units (e.g., km/hr to m/sec)
  • Knowledge of the quadratic formula for solving equations
  • Basic principles of relative motion in physics
NEXT STEPS
  • Learn how to derive kinematic equations for different scenarios
  • Study unit conversion techniques, particularly for speed and distance
  • Explore applications of the quadratic formula in physics problems
  • Investigate graphical representations of motion, including position vs. time graphs
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion equations in real-world scenarios.

Rker
Messages
14
Reaction score
0

Homework Statement



A car is traveling at 80 km/hr in a school zone. A police car is at rest in the parking lot of the school. It takes the policeman 0.5 sec to react before he begins accelerating after the speeder with an acceleration of 8 m/sec2.

(a) How far has each car traveled when the police car catches the speeder?
(b) How fast is the police car going when it catches the speeder?
(c) Make a sketch of the position of both cars as a function of time?

Homework Equations



2vxni8z.jpg


There may be different equation(s). These are just the main ones we're using for this unit.

The Attempt at a Solution



28hlifb.jpg


My setup is correct, but I'm having difficulty finding T. I tried plugging variables in equations, and it seems nothing's working. Once T is found, I'll hopefully be able to solve parts (a), (b), and (c) with ease.
 
Physics news on Phys.org
As you have correctly indicated, Xf,s = Xf,p.

What does the formula for Xf give you in both cases? (Be especially careful about the value of Xi,p!)

When you set these formulas equal to each other, you will get a single equation for T.
 
Thank you for the fairly quick reply. I set the formulas equal to each other and got this:

0 = -4(m/sec^2)t^2 + 22.22(m/sec)t + 11.11m

Is that correct so far? And, if so, would I just use the quadratic formula to find positive T?
 
After a quick check, that looks like the correct answer. Just to be sure, can you tell me what you took for Xi,s and Xi,p (actually, you can take anything for Xi,s, for example -- all that matters is Xi,p - Xi,s)?

And you are completely right about solving it, too :)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
8K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K