How to Calculate the Lower Limit of the Diameter of an Icy Minor Planet?

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To calculate the lower limit of the diameter of an icy minor planet, equate the central pressure to the maximum pressure cold ice can sustain, approximately 40 MPa. The hydrostatic equilibrium equation and mass conservation can be used to derive the relationship between pressure and radius. By integrating the equations, it is established that the central pressure must exceed a specific formula involving the mass and radius of the planet. To find the diameter, set the central pressure equal to 40 MPa and solve for the radius, using the known density of ice to relate mass and radius. This approach allows for the determination of the diameter, although the mass of a specific icy minor planet, such as Ceres, may be needed for accurate calculations.
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I have a homework question that I am having troubles with.

Q: By equating the pressure at the centre of an icy planetesimal to the maximum pressure that cold ice can sustain without deforming, about 40 MPa, find a lower limit to the diameter of an icy minor planet.

The part I don't understand is the "lower limit to the diameter"
Do I use: Pcentral >\frac{GM^{2}}{8πr^{4}}dm

I just don't know how to get the diameter...
 
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I don't know where your formula comes from, but you need some relation between size (like the radius r in your formula?) and pressure in the center, and then let the pressure in the center be 40MPa.
This looks more like an upper limit, however.
 
mfb said:
I don't know where your formula comes from
I did:
\frac{dP}{dr}=ρg
and g=\frac{GM}{r^2}
so \frac{dP}{dr}=\frac{-GMρ}{r^2} (Hydrostatic equilibrium equation)
and \frac{dM}{dr}=4πr^{2}ρ (equation of mass conservation)

by dividing the two equations: \frac{dP/dr}{dM/dr}=\frac{dP}{dM}=\frac{-GM}{4πr^4}

integration: P_{c}-P_{s}=-\int^{M_{c}}_{M_{s}}(\frac{GM}{4πr^4})dM
P_{c} and P_{s} are pressure at centre and surface of the planet
and by setting M_{c}=0 and by switching the intergral:

P_{c}-P_{s}=\int^{M_{s}}_{0}(\frac{GM}{4πr^4})dM

and

\int^{M_{s}}_{0}(\frac{GM}{4πr^4})dM > \int^{M_{s}}_{0}(\frac{GM}{4πr^{4}_{s}})dM = \frac{GM^{2}_{s}}{8πr^{4}_{s}}

hence

P_{c}-P_{s}>\frac{GM^{2}_{s}}{8πr^{4}_{s}}

and by approximating that the pressure at the surface to be zero (P_{s}=0)
we get:

P_{c}>\frac{GM^{2}_{s}}{8πr^{4}_{s}}


mfb said:
you need some relation between size (like the radius r in your formula?) and pressure in the center, and then let the pressure in the center be 40MPa.

So are you saying I should do:

40MPa>\frac{GM^{2}_{s}}{8πr^{4}_{s}}?

I figure I have to solve for r and then obtain the diameter from there but I am stuck because I am not given the mass... (or do I use a mass of an icy minor planet like Ceres?)
 
Last edited:
Your formula differs from the one in the first post now.

You know the density of ice, this gives the relation radius<->mass,
 
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