How to Convert a 8V Voltmeter to 20V with Same Ohms per Volt Rating?

AI Thread Summary
To convert an 8V voltmeter to read 20V at full scale deflection, an additional resistance of 60,000 ohms must be added in series, maintaining the original grading of 5000 ohms/volt. If the voltmeter were graded at 2000 ohms/volt, the required series resistance would be only 24,000 ohms, which is less preferred due to the higher current drawn, potentially affecting circuit measurements. The grading of ohms per volt indicates the reciprocal of the current allowed at full-scale deflection, with higher values indicating lower current draw. A higher resistance voltmeter is generally favored for accurate voltage measurements in circuits. This discussion highlights the importance of voltmeter grading in circuit applications.
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Homework Statement



A voltmeter reads 8V at full scale deflection, and is graded according to its resistance per volt at full scale deflection as 5000 ohms / volt. How will you convert it into a voltmeter that reads 20V at full scale deflection? Will it still be graded as 5000 ohms / volt.? Will you prefer this voltmeter to one that is graded ats 2000 ohms /volt?

Homework Equations


Application of Ohm's Law


The Attempt at a Solution



Let R = voltmeter resistance
I = current through voltmeter for full scale deflection

If the voltmeter has to read 20V at full scale deflection, we need an additional resistance r in series with it. Thus

8/R = 20/R+r
R = 5000 *8 (since the voltmeter is graded as 5000 ohms/V for full scale deflection
of 8V)
1/5000 = 20/40000 +r
r= 60000 ohms
The above has been calculated using the voltmeter grading as 5000 ohms /V.
I need some clues to proceed further with the next part of the question as I am not sure as to whether my way of looking at the voltmeter grading is correct or not.
 
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Your solution is correct, go ahead.

ehild
 


OK. Now if we consider a voltmeter grading of 2000 ohms / V, we get the value of external resistance as 24000 ohms. This being lower than the earlier value of 60000 ohms, is less preferred because the higher the resistance, the less the current drawn by the voltmeter. Trust this solution is in order. Please advise. Thanks.
 


The ohm/volt value means reciprocal current, the reciprocal of the current which is allowed to flow through the voltmeter at full-scale deflection. Does it change if you connect a series resistance to the voltmeter?
Less ohm/volt means higher allowed current at the same full-scale voltage, and lower resistivity of the voltmeter. As you said, this is less preferred in measuring voltage in a circuit, as a lower-resistivity voltmeter would influence the currents in the circuit at higher extent as a high-resistivity meter.

ehild
 


Thanks a lot for your help.
 
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