How to define a solid cyclinder or any solid objects parametrically?

  • Thread starter Thread starter DorumonSg
  • Start date Start date
  • Tags Tags
    Solid
DorumonSg
Messages
61
Reaction score
0
How to define a solid cyclinder or any solid objects parametrically?

I can't figure out what do I do with the z axis for example a Cylinder :

x = 0.5*cos(theta)
y = sin(theta)

0*pi <= theta <= 2*pi

This will make an eclipse.

But wad about z?

I know we have to stretch z to the height we want. But how do we do that?

Lets take it I want the height to be 2.

So :

z = t

0 <= t <= 2

But it won't work. Becuz' it only stretches the z axis, infact it not only just stretches the z axis, it stretches the eclipse I defined using x y to the point z = 2 on the z axis.

I can't figure out how to stretch the eclipse properly on the z axis so it becomes a proper solid cyclinder?
 
Physics news on Phys.org
Oh and another question.

According to the notes my teacher gave me,

The equation of a circle is r^2 - x^2 - y^2 = 0 where r is the radius.

While the equation for a circle disk(half space) is

r^2 - x^2 - y^2 >= 0

Why is this so? And why does half space mean in 2D?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top