How to derive Relation between Levi-civita Density and Kronecker's Delta?

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SUMMARY

The discussion focuses on deriving the relationship between Levi-Civita Density and Kronecker's Delta, specifically the equation k=13 εmnk εijk = δmi δnj - δmj δni. Participants emphasize that the right-hand side must be antisymmetric in the indices m, n and i, j, suggesting that the derivation involves recognizing this antisymmetry and utilizing properties of the Levi-Civita symbol and Kronecker delta. The discussion indicates that a purely analytical derivation may not be feasible without considering these properties.

PREREQUISITES
  • Understanding of Levi-Civita symbol properties
  • Familiarity with Kronecker delta notation
  • Basic knowledge of tensor algebra
  • Experience with antisymmetry in mathematical expressions
NEXT STEPS
  • Study the properties of the Levi-Civita symbol in depth
  • Explore the applications of Kronecker delta in tensor calculus
  • Learn about antisymmetric tensors and their implications
  • Investigate analytical methods for deriving tensor relationships
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Mathematicians, physicists, and students studying advanced algebra or tensor analysis will benefit from this discussion, particularly those interested in the applications of Levi-Civita density and Kronecker's delta in theoretical frameworks.

Abir Sarkar
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The Relation between Levi-Civita Density and Kroneckers Delta as follows



\sum^{3}_{k=1} \epsilon_{mnk} \epsilon_{ijk} = \delta_{mi} \delta_{nj} - \delta_{mj} \delta_{ni}​



Logically we can satisfy both sides of the expression but Can anyone tell me how to derive this analytically ?
 
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I don't think you can purely derive it, just consider that the RHS must be a-symmetric in m,n and i,j, so it must be an antisymmetrized product of deltas.
 

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