How to Derive the Finite Difference Laplacian in Various Coordinates?

mojomike
Messages
5
Reaction score
0
Updated: Finite difference of Laplacian in spherical

Homework Statement



I understand the problem a little better now and am revising my original plea for help. I don't actually need to integrate the expression. Integration was just one technique of arriving at a finite difference expression for the Cartesian Laplacian. I'm now convinced there is a simpler way to do it, possibly with some kind of expansion.

Here's what I'm seeking: A finite difference, 1-dimensional expression of the Laplacian, expressed so that it can be made to work in cartesian(n=0), cylindrical(n=1), or shperical(n=2) coordinates.

2 φ(r) dr =

\frac{1}{r^{n}}\frac{\partial}{\partial r}r^{n}\frac{\partial}{\partial r}\Phi(r) dr<br />

Homework Equations

see above

The Attempt at a Solution



I have solved the finite difference laplacian in Cartesian coordinates, which is pretty easy. I just don't know how to express that double derivative with the rn factor in the middle in finite difference form. I'll continue to update my request as I make progress, so nobody thinks I'm loafing here. Thanks again.

,Mike S
 
Last edited:
Physics news on Phys.org
Problem resolved. Thanks anyway!
 
Dear Mike,

Since you've resolved the problem, perhaps you could also post the solution? This way, when someone with a similar problem searches for it, they will find an answer instead of just the question.

Cheers,
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top