How to determine the brightness of a light bulb

AI Thread Summary
The brightness of a light bulb is influenced by both current and voltage, with power being the key measure of brightness. While more current and less resistance generally lead to increased brightness, the configuration of the circuit plays a crucial role. In an ideal scenario where an incandescent bulb is 100% efficient, all power would convert to visible light, but in reality, much energy is lost as heat. Brightness can be quantified by the formula I^2R, indicating that reducing resistance while increasing current enhances brightness. Ultimately, the relationship between current, voltage, and resistance determines the overall brightness of the bulb.
cy19861126
Messages
69
Reaction score
0
In general, does more current/less resistence mean the brighter of the light bulb? How does voltage take into account in this case
 
Physics news on Phys.org
Both the current and voltage contributes to the brightness. It just depends on the configuration. If an incandescent is 100% efficient (with it isn't btw), that means all power (V*I) would be used to produce visible light rather than 90% being wasted as heat.
 
"Brightness" is a measure of power, so at constant voltage power is I^2R. If resistance is decreased and current is increased by an equal factor, the increase in current counts for more and the bulb will appear brighter
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top