How to Draw a Bode Plot Without a School Book

AI Thread Summary
To draw a Bode plot for the transfer function H(S) = s + 10, focus on the asymptotes, as they represent the key characteristics of the system. The presence of a zero at -10 can be identified, which influences the plot's magnitude and phase. Understanding that s represents a complex frequency, specifically s = σ + jω, is crucial for analyzing the frequency response. When creating the plot, you will primarily calculate |H(jω)| for the magnitude and the phase angle. Familiarity with these concepts is essential for accurately drawing the Bode plot without a textbook.
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Homework Statement



How do you draw a bode plot?
I have a simple equation: H(S)=s+10 but no school book. Can you teach me?
 
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How about a tutorial?
http://www.facstaff.bucknell.edu/mastascu/elessonsHTML/Freq/Freq5.html

When you're drawing by hand, usually only the asymptotes are required; the effects of zeros, poles, higher ordered zeros and poles, and most of the simple cases are usually tabulated in the first chapter of any controls textbook.

EDIT: Summary for drawing asymptotic transfer functions (agrees with what I remember):
http://en.wikipedia.org/wiki/Bode_plot#Rules_for_hand-made_Bode_plot

EDIT: This post might've been better in the EE or Engineering homework subforum.

EDIT: Thought I recognized the username... Since you asked a MATLAB question, you may also want to look in this thread:
https://www.physicsforums.com/showthread.php?t=303967
 
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I don´t have any poles and no zeros either.
So what do I do then? Or do I have one zero? = -10 ?

But I really don´t understand those webpages because they all have jw sth..
 
Yes, there's one zero. I'm not sure how far along you are in your complex math or controls course, but s is the 'generic' frequency s=\sigma+j\omega. If you're finding the frequency response (as you are in a Bode plot) you're only concerned with the situation where \sigma is zero and frequency is imaginary (i.e. sinusoidal). That's why some of the previously-linked resources use j\omega instead of s (even though the transfer function is given in terms of s)

Put another way, if your transfer function is called H(s), you're finding |H(jw)| (the magnitude of the frequency response) and the phase
 
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