How to find decceleration of the car

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To find the deceleration of a car, it's important to understand the role of friction between the tires and the road. The coefficient of friction is 0.7, and when brakes are applied, the tires decelerate at 2 m/s. Friction acts to oppose the motion of the car, which means it increases deceleration when brakes are applied. The discussion emphasizes the need to consider how friction interacts with the forces at play during braking. Understanding these concepts is crucial for calculating the final deceleration accurately.
vastandfurious
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Hello,
I have a question to figure out that asks for the final decceleration of the car, if the coefficient between the road and tire is 0.7 and the guy in the car pushes the breaks causing the tire to deccelearate at 2 m/s...hmmm...It is a simple question, but I cannot figure out if the friction increases the deceleration or decreases it...Any help is appreciated...

EDIT: BTW just noticed, that I can't post homework questions here...my bad
 
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Welcome to PF,

vastandfurious said:
It is a simple question, but I cannot figure out if the friction increases the deceleration or decreases it

all you need to do is ask yourself, does the frictional force oppose or promote the motion of the car? What does friction do?

-Hoot:smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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