How to find the temperature of a black body?

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Homework Help Overview

The discussion revolves around determining the temperature of a black body that emits photons at a frequency of 4 GHz, with a given photon energy. Participants explore the relationship between frequency, wavelength, and temperature in the context of black body radiation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of formulas involving Planck's Constant and Wien's Displacement Law to relate frequency and temperature. There are questions about the correct representation of the problem, particularly regarding the terminology used (protons vs. photons).

Discussion Status

Several participants are actively engaging with the problem, offering guidance on relevant equations and questioning the original poster's setup. There is a recognition of potential confusion regarding the application of black body radiation principles, but no consensus has been reached on the correct approach to find the temperature.

Contextual Notes

There is a mention of the original poster's uncertainty about the problem's formulation and whether it is part of an online homework assignment. The discussion also touches on the implications of the frequency being in the microwave range, which may challenge typical black body radiation assumptions.

sphys4
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Homework Statement


It emits protons with a frequency of 4 GHz, and has a photon energy of 2.65E-24 J.

I tried to use the formula lambda=c/f=vT, but i am somehow getting a negative answer which doesn't make sense when trying to find temperature in (K).

Any help is greatly appreciated.
 
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You'll need the equation involving Planck's Constant, denoted by h[/color]
 
NascentOxygen said:
You'll need the equation involving Planck's Constant, denoted by h[/color]

E=hc/lambda? So i solve for lambda and plug it into my above equation? Does v=4E+9?
 
sphys4 said:

Homework Statement


It emits protons with a frequency of 4 GHz, and has a photon energy of 2.65E-24 J.

Are you sure you have represented the question correctly? Because a hot body emits photons over a whole spectrum of energies.

And I presume you didn't intend to write "protons"? Otherwise, I'm outta here. :eek:
 
Last edited:
NascentOxygen said:
Are you sure you have represented the question correctly? Because a hot body emits photons over a whole spectrum of energies.

And I presume you didn't intend to write "protons"? Otherwise, I'm outta here. :eek:

Ahh * photons.

And yes, this is the problem.
Suppose a blackbody emits photons strongly with a frequency near 4 GHz. What is the photon energy? And then i found the value that i stated above (in J), which is correct.

The question then asks for the temperature of the black body and that's where I am lost.
 
The wavelength where the radiation is maximum multiplied by the temperature is constant, lambda * T = b. How do you get the temperature?

ehild
 
sphys4 said:
Okay so i found lamba which i got .075

0.075m seems correct. So at 4GHz we are talking about microwave energy, way below visible light. (I wonder is this venturing beyond the limits of black body radiation equations?)

then divided that by b (the constant) and got 25.88 which is still wrong. :(

To find T you need to divide b by lambda.

Considering that the lowest temperature found in outer space is about 3 Kelvin, then I think you've taken us to another universe. :cool:

At least it's not a negative Kelvin. :rolleyes:

Did you invent this question, or it is out of a book?
 
Last edited:
  • #10
NascentOxygen said:
0.075m seems correct. So at 4GHz we are talking about microwave energy, way below visible light. (I wonder is this venturing beyond the limits of black body radiation equations?)



To find T you need to divide b by lambda.

Considering that the lowest temperature found in outer space is about 3 Kelvin, then I think you've taken us to another universe. :cool:

At least it's not a negative Kelvin. :rolleyes:

Did you invent this question, or it is out of a book?

It's online homework that i copied and pasted, it's okay though.. thank you for your time and attempting!
 

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