How to Find Thevenin Equivalent Circuit | Step-by-Step Guide

  • Thread starter Thread starter kliker
  • Start date Start date
  • Tags Tags
    Circuit Thevenin
AI Thread Summary
To find the Thevenin equivalent circuit, the voltage across the load (Vth) was calculated as 10 V by summing -10 V and 20 V. The Thevenin resistance (Rth) was determined to be 6 Ohms. The calculations appear to be correct, but there is uncertainty regarding the accuracy of the results. Further verification or confirmation from peers may be beneficial. The discussion highlights the importance of double-checking calculations in circuit analysis.
kliker
Messages
102
Reaction score
0

Homework Statement



[PLAIN]http://img684.imageshack.us/img684/9092/asdrc.jpg
given this circuit find the thevenin equivalent

the 4 ohm resistor is the load

The Attempt at a Solution



at first I found Vth which is Vth = -10+20 = 10 V

then i found Rth which is 6 Ohms

but I am not sure if I am correct
 
Last edited by a moderator:
Physics news on Phys.org
Looks good!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top