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How to fix this electric circuit

  • Thread starter orpheus
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  • #1
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Homework Statement



I'm not sure if the construction of this circuit is correct, so that both lamps, which are the same, shine equally brightly. Otherwise only the resistors are given. If it's wrong, what else would it look like? And why?[/B]

1537595868640-940372466-jpg.jpg


Homework Equations


I guess the laws of Kirchoff and Ohm

The Attempt at a Solution



check this link:
[/B]
https://share-your-photo.com/6ef822170a
 

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  • #2
Charles Link
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When I clicked on the photo, google has ads in the way, so that I can not see it completely. Can you please try to find some other way to upload the diagram.
 
  • #3
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Yes, sorry, now it should work. :)
 

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  • #4
Charles Link
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By "fixing" the circuit, you will need to add a resistor at the upper left of some value to be determined =perhaps that value is zero. Suggestion is to try short circuiting that part first and see what you get. Presently, the bulb on the upper right will not light at all. You need to put in some of the work here though. The Physics Forums homework helpers can help you to work to the solution, but we are not allowed to provide the answer. You must do the work to get to the answer.
 
  • #5
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We are not allowed to add something to circuit. We should just switch resistors. I guess. I cant solve it.
 
  • #6
Charles Link
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You are at least going to need to close the circuit at the upper left. The instructions don;t seem to be entirely clear on this problem, but again the first thing I would try is simply close the circuit at the upper left. And you need to write out the current and voltage equations. It takes a little work, but when you get tested on the material, they are not going to write the equations for you. That is what homeworks are for=to learn by trial and error. ## \\ ## One way to get them to shine equally bright is to simply put the bulbs next to each other in series in the circuit=they aren't real clear on what you are allowed to do to the circuit. ## \\ ## Edit: My suggestion of shorting the circuit at the upper left will not work. This one is actually kind of simple now that I have looked it over carefully, and it does not require extensive circuit analysis. If you look at the bulb at the lower left, it is in series circuit with the voltage source with resistances totaling ## R=2.3 \, k \Omega ## . How would you modify the circuit to get the same thing for the other bulb? That will give you the solution you need.
 
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  • #7
Charles Link
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See my "Edit" above= (post 6). This one is actually quite simple. And note: The ## R=100 \, \Omega ## at the lower right will be shared by both circuit loops, but that is ok. In the circuit that is the correct solution, that resistor will simply have 2x the current through that all of the other resistors have. The solution involves one simple step.
 
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  • #8
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So I am actually not far from solution?
 
  • #9
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I guess I have the solution but I am not sure.
I am not more able draw because I went for a time away from home (now in train), so there is no possibility write it down for me.
 
  • #10
Charles Link
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