How to Integrate cos4 x Using the Double Angle Formula

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Homework Statement



Find the integral of cos4 xdx

Homework Equations



cos2x = 2cos2x-1
cos2x = (cos2x+1)/2

The Attempt at a Solution



I tried using cos4x = cos2x * cos2x and i simplified it to
cos4x = ((cos2x)2 + 2cos2x + 1)/4

I'm not sure if this is right. How do i go about getting the integral of this expression if it is correct. Thanks
 
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So far, so good. You just need to take it one step farther, by replacing (cos2x)2 with (cos4x + 1)/2. At that point you'll have an integral with four terms, and you can split this up into four integrals, each of which is pretty easy.
 
Hey i got the answer (sin4x)/32 + (sin2x)/4 + (3x)/8 + C which seems to be right. Thanks for your help :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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