How to Prove the Commutator Relation for Quantum Spin Operators?

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Homework Statement



Using the orthonormality of |+\rangle and |-\rangle, prove

[S_i,S_j]= i \varepsilon_{ijk}S_k

where
S_x = \frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |
S_y = -\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |
S_z = \frac{\hbar}{2}|+\rangle \langle + | - | - \rangle \langle - |


The Attempt at a Solution



Since S_x and S_y commute, their commutator should be zero which contradicts [S_x,S_y]= i S_z. What am I missing here?
 
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S_x and S_y does not commute, check again.

If you are unsure, please write the procedure you did to get that S_x and S_y commutes.
 
Umm, is this not right?

[S_x,S_y] = \frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |\left(-\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | \right)<br /> <br /> -\left(-\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | \right)\frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | = 0?
 
Is this a typo or what?
 
jdstokes said:
Is this a typo or what?

Must be; the way it's written,

S_y = -iS_x.
 
jdstokes You must use paranthesis more carefully!

According to my copy of Sakurai:

S_y = \frac{i\hbar}{2}(-|+\rangle \langle - | + | - \rangle \langle + |)
 
OMG why do I miss these obvious things!

Thanks for your patience malawi_glenn and George.
 
If you guys have a spare moment, would you please have a look at my new post in the quantum physics forum?
 
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