How to Solve Energy & Work Problems?

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To solve the energy and work problems, the first task involves calculating the power developed by a conveyor belt transporting bundles of newspapers. The correct approach requires determining the total work done against gravity for the mass of the newspapers and converting it to power in Watts. For the second problem, the work needed to stretch the spring should be calculated using the area under the force vs. displacement graph, rather than simply multiplying the change in force by distance. Clarifications on units and the correct application of work formulas are essential for accurate solutions. Understanding these concepts is crucial for tackling physics problems effectively.
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Homework Statement


1. A 10.5 m long conveyor belt, inclined at 30.0°, is used to transport bundles of newspapers from the mailroom up to the cargo bay to be loaded on to delivery trucks. Each newspaper has a mass of 1.0 kg, and there are 28 newspapers per bundle. Determine the power that the conveyor develops if it delivers 15 bundles per minute.

2. Use the graph in the diagram
2ilhhyx.jpg


to find the work needed to stretch the spring from 0.14 m to 0.26 m.

***

any or all help appreciated...THANKS SO MUCH <33


Homework Equations


For both 1 & 2...
basic trig, W=F*d, P = change in W / Change in T, KE = .5mv^2, PE = mgh (but I'm confused if I even need KE or PE to solve these...?)


The Attempt at a Solution


For 1, I drew out the ramp and all the force components. I determined the force per bundle to be 137.2 N per bundle, and the total Work to be 1440.6...I multiplied this by 15, to get the answer, but it wasn't correct...I'm just so confused as to how to approach this.

2. I added the change in force at those two points, and multiplied it by distance traveled which is .26 - .14 m. Got this wrong too...

any or all help appreciated. i suck at physics. thanks so much.
 
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For #1, are the units in your final answer correct? I assume they want it in Watts (J/s)

For #2, I'm not sure I understand what you are doing. What do you mean by "change in force at those two points"?
 

The Attempt at a Solution


For 1, I drew out the ramp and all the force components. I determined the force per bundle to be 137.2 N per bundle, and the total Work to be 1440.6...I multiplied this by 15, to get the answer, but it wasn't correct...I'm just so confused as to how to approach this.

This looks right to me.
2. I added the change in force at those two points, and multiplied it by distance traveled which is .26 - .14 m. Got this wrong too...

Work done is just the area under the graph, since W=Fd for constant F and d, and the graph can be broken down into an infinite number of infinitely thin rectangular tiles each with constant F and d.
 
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