How you could find E'/E at the min of 180 degrees

[dranger35]

From the Comptom Scattering formula, you get
(E-E')/E E' = (1/mc^2)(1-cos@).

Can someone tell me how you could find E'/E at the min of 180 degrees. I've tried using the conjugate, and other methods, but I can't get E'/E out of it. I must be doing something wrong. Thanks.

 

[dextercioby]

\frac{1}{E'}-\frac{1}{E}=\frac{2}{mc^{2}} \Rightarrow \frac{E'}{E}=\frac{mc^{2}}{2E+mc^{2}}

Daniel.

 

[dranger35]

Wait

... is the answer just E'/E = mc^2/(2E + mc^2) or
mc^2/(2E + mc^2) (1- cos@).

 

[dextercioby]

You said about 180 \mbox{deg},right...?I assumed you did,and used this fact.How would my formula change,if,instead of that particular value for the scattering angle,you'd use the general case?
It's not difficult,it's simple algebra.

Daniel.