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Idea04
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I would like to know how to calculate the flow rate of water under compression by a hydraulic weight. How do you calculate using the value of the weight on top of the water and the height of the water in a straight column?
Do you want to know the flow rate of the water out of a hole in the side fo the cylinder at a certain depth?Idea04 said:I would like to know how to calculate the flow rate of water under compression by a hydraulic weight. How do you calculate using the value of the weight on top of the water and the height of the water in a straight column?
But velocity does not just depend on the height of water. Velocity depends on the area of the hole, and the extra weight that is added.Idea04 said:well the problem I have is that the equation I used was .6 x s x((2 x p)^2)
where s was the area of the hole in square meters and p was the pressure in bars. I think this could be the wrong equation because from a 7 foot height column .5" diameter hole I was gettting around .01644308 liters a second. And from another site I saw a chart where over 7 feet head of water was getting 22 feet per second velocity rate.
The difference in pressure between the inside and outside of the tank multiplied by the area of the hole gives you the force pushing the water out. The higher the outside the pressure, the less force pushing the water out (hence less velocity).And another thing atmosphere pressure has to play a role. so for example if you take a bottle of water and turn it upside down, the water flows kind of in clumps because air is rushing into equalize the pressure. But if you have a hole on top where air can enter the water flows more smoothly and faster. Because the water rushing out the bottom doesn't have to fight the force of air rushing in through the bottom. So my question if how do you add atmospheric pressure to water pressure? will the pressure increase in the example of the open top bottle of water.
I was hoping you would work it out from what I gave you.Idea04 said:Thanks for the help. But the actual equation that I am looking for uses the values of depth of the water, fluid density, spout exit diameter and discharge coefficient. It is to give you the value of velocity in meters per second. Can someone give me that equation? Thanks.
To calculate water flow rate under compression, you will need to measure the pressure and volume of the water. The formula for calculating flow rate is Q = AV, where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the water velocity.
The most common units for measuring water flow rate are gallons per minute (GPM) and liters per second (L/s). However, other units such as cubic meters per hour (m³/h) and cubic feet per second (ft³/s) may also be used.
Water density does not have a direct effect on flow rate under compression. However, it can affect the pressure and volume of the water, which are important factors in calculating flow rate.
Yes, water flow rate under compression can be increased by increasing the pressure or decreasing the cross-sectional area of the pipe. However, there may be limitations based on the capacity of the pipe and the pump.
The accuracy of calculations for water flow rate under compression depends on the accuracy of the measurements for pressure and volume. It is important to use precise instruments and to properly calibrate them for the most accurate results.