I need to know if i correct (Chemistry)

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In summary, the compound with an empirical formula of CH2 and a molar mass of 56 g/mol will have a molecular formula of C4H8. The oxidation number of manganese in the compound KMnO4 is most likely +7.
  • #1
omni
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1
if is known that for some Compound have Empirical formula CH2 and molar mass of 56 g/mol

so the Molecular formula of this Compound will be C4H8 ?


and other Question that i need to know if i correct is: the Oxidation number of KMnO4 is +7 ?

thanks.
 
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  • #2
omni said:
so the Molecular formula of this Compound will be C4H8 ?

Yes.

is: the Oxidation number of KMnO4 is +7 ?

Oxidation number is a property of atom, not a molecule. But I guess it is just a lousy wording and you are on the right track.
 
  • #3
hi. thank you for yours answer
about KMnO4 i got 4 Different Options and this was my Options :

A)+7
B)+2
C)+3
D)+4
so found is A what do you say?
and thanks again.
 
  • #4
You still don't understand. There is no such thing as oxidation number of KMnO4. But K in KMnO4 has oxidation number of +1. O in KMnO4 has oxidation number of -2. And so on.
 
  • #5
The question probably asked for the oxidation number for manganese in the compound KMnO4.
 
  • #6
yes yes exactly as chemisttree told is asked about manganese in the compound KMnO4 so the answer still the same?

and sorry about the Bad wording.
thanks.
 
  • #7
omni said:
yes yes exactly as chemisttree told is asked about manganese in the compound

I hoped you will get in on your own.

+7 it is.
 

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