Ideal circuit with 4 resistances and one emf.

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AI Thread Summary
The discussion focuses on solving a circuit problem involving four resistors and an ideal battery with an emf of 12.0 V. Participants seek to determine the size and direction of the current (i1) and the energy dissipated by the resistors over one minute. There is confusion regarding calculating the equivalent resistance and the correct method for finding the current through each resistor. Participants confirm that to find the energy dissipated, the power formula P = I²R should be used, emphasizing the need to know the current through each resistor. The original poster eventually resolves the problem independently.
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Homework Statement


In the figure below, R1 = 5.50 , R2 = 18.0 and the ideal battery has an emf E= 12.0 V.
(a) What is the size and direction of current i1? (Take right to be positive.)

(b) How much energy is dissipated by all four resistors in 1.00 min?

Homework Equations


I = E/R
resistive dissipation
P=i2R
P=v2/R

The Attempt at a Solution


I am having trouble trying to find the equivalent resistance to find the current i1. I know it should be in the positive direction to the right.

For part b should i just add up the dissapations for the 4 resistors?
 
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What figure? =D
For part b you are correct, P = I2R is the energy dissipated on that resistor, so you'd have to find the corresponding value of the current going through a particular resistor.
 
noumed said:
What figure? =D
For part b you are correct, P = I2R is the energy dissipated on that resistor, so you'd have to find the corresponding value of the current going through a particular resistor.

I forgot to attach it but i figured the problem out anyway.
 

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