Ideal gas law: can you use it to find P during exsolution?

AI Thread Summary
The discussion explores whether the ideal gas law can be applied to determine pressure during exsolution in a shaken soda bottle. It suggests that the difference between the actual volume increase of the bottle and the theoretical volume the gas would occupy if uncontained could be used to calculate pressure. The formula proposed is PRESSURE = mRT/V, where V is the volume increase and m is the density of the gas multiplied by the volume it would fill if not contained. The conversation acknowledges that while pressure keeps some gas in solution, the scenario involves fluid rising above its saturation pressure, allowing for some expansion. Overall, the feasibility of using the ideal gas law in this context is questioned, indicating a need for further analysis.
@PinkGeology
Messages
5
Reaction score
0
If you shake up a bottle of soda and it gets slightly larger because the disturbed gas in solution is trying to expand but cannot, could you use the difference in (THE SMALL AMOUNT THE BOTTLE ACTUALLY SWELLED) and the (POTENTIAL AMOUNT THE GAS WOULD SWELL IF NOT CONTAINED) to determine the pressure in the bottle?

e.g. PRESSURE = mRT/V ... where V is the tiny amount the bottle swelled and m = density_gas*V1 where V1 is the volume this exsolved amount gas would fill if not contained?

(and let's just pretend you knew how much gas exsolved when you shook it ... because we pretend in physics).

Or am I just barking up the wrong tree entirely? :)
 
Physics news on Phys.org
By the way, I know the pressure would keep a certain amount of gas in solution regardless of what it "wanted" to do, but in my real problem (which seemed to annoying long and complicated to post here) the fluid will be ascending to a point above it's saturation pressure and have more freedom (although not total) to expand than soda in a bottle.
 
Assume that this is a case where by sheer coincidence, two sources of coherent single-frequency EM wave pulses with equal duration are both fired in opposing directions, with both carrying the same frequency and amplitude and orientation. These two waves meet head-on while moving in opposing directions, and their phases are precisely offset by 180 degrees so that each trough of one wave meets with the crest of the other. This should be true for both the electric and magnetic components of...
Back
Top