How Is Volume Affected by Pressure in an Ideal Gas?

AI Thread Summary
The discussion centers on calculating the volume change of a monatomic ideal gas under adiabatic compression from an initial pressure of 110 kPa to a final pressure of 150 kPa in a thermally insulated container. The key equation for this scenario is the adiabatic condition, which states that P_iV_i^γ = P_fV_f^γ, where γ is the heat capacity ratio. Participants clarify that the relationship between pressure and volume during adiabatic processes differs from isothermal processes, emphasizing that temperature also changes. The ideal gas law remains applicable, but adjustments must be made to account for the adiabatic nature of the compression. Ultimately, the correct approach involves using the adiabatic condition to find the new volume.
MozAngeles
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Homework Statement


A monatomic ideal gas is held in a thermally insulated container with a volume of 0.0900m 3. The pressure of the gas is 110 kPa, and its temperature is 347 K.
To what volume must the gas be compressed to increase its pressure to 150 kPa?
To what volume must the gas be compressed to increase its pressure to 150 kPa?

Homework Equations



PV=nRT
\Delta=Q-W
W=P\DeltaV

The Attempt at a Solution


P1*V1/P2
=(110*.09)/(150)
= .0660 this is wrong i don't know what I'm missing..
 
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MozAngeles said:

Homework Statement


A monatomic ideal gas is held in a thermally insulated container with a volume of 0.0900m 3. The pressure of the gas is 110 kPa, and its temperature is 347 K.
To what volume must the gas be compressed to increase its pressure to 150 kPa?
To what volume must the gas be compressed to increase its pressure to 150 kPa?

Homework Equations



PV=nRT
\Delta=Q-W
W=P\DeltaV

The Attempt at a Solution


P1*V1/P2
=(110*.09)/(150)
= .0660 this is wrong i don't know what I'm missing..
The key is the thermally insulated container. What kind of compression is this? What is the relationship between P and V in such a compression? (hint: it has something to do with \gamma)

AM
 
So it is a adiabatic compression right?
So would I use
PiVi\gamma=PfVf\gamma
 
MozAngeles said:
So it is a adiabatic compression right?
So would I use
PiVi\gamma=PfVf\gamma
If you mean:

P_iV_i^{\gamma} = P_fV_f^{\gamma}

ie: PV^{\gamma} = K = constant

then, yes

AM
 
and then for the second part of the question I am still stumped, I thought you could use
Vi/Ti=Vf/Tf

and this isn't right, probably because of the fact that it is adiabatic?
but the equation is PV\gamma= constant
so that doesn't include temperature, and now I'm lost..
 
MozAngeles said:
and then for the second part of the question I am still stumped, I thought you could use
Vi/Ti=Vf/Tf

and this isn't right, probably because of the fact that it is adiabatic?
but the equation is PV\gamma= constant
so that doesn't include temperature, and now I'm lost..
Vi/Ti=Vf/Tf is true only if P is constant. In an adiabatic change, P, V and T all change. The ideal gas law still applies. But in order to determine how T changes you have to know how P and V change.

If you substitute P = nRT/V into the adiabatic condition, it becomes:

TV^{(\gamma-1)} = PV^\gamma/nR = K/nR = \text{constant}

That is what you have to use.

AM
 
thanks figured it out
 
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