Ideal op amp (current to voltage converter + inverting)

AI Thread Summary
To derive the output voltage (Vo) in relation to the input current (Iin) for an ideal op-amp current-to-voltage converter, the equation Vo = -R2/R1(-IinRf) can be used. The load resistor (RL) does not need to be included in the gain equation as long as the second op-amp's output can drive RL effectively. It is essential to verify the op-amp's output current capability to ensure it can handle the expected voltage swing based on the gain equation. If the op-amp exceeds its output current rating, it may lead to performance issues. Understanding these parameters is crucial for accurate circuit design.
naspek
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Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL[/size]
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg
 
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naspek said:

Homework Statement



Hey there.. need helps here..
The question is..
Derive an expression relating the output voltage, Vo to the input current, Iin.

The Attempt at a Solution



i try to derive it.. but..
got problem with RL[/size]
V1 = -IinRf
Vo =- R2/R1(-IinRf) how to include Rl in my derivation?

currenttovoltageconverter.jpg

Good question. As long as the 2nd opamp's output is capable of driving RL, you don't need to include it in the gain equation. In real life, you would check the output current capability of the opamp, figure out the voltage swing based on your gain equation (for whatever values of Iin you expect), and make sure you weren't exceeding that output current rating.
 
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