Idempotent Matrix homework help

  • Thread starter Thread starter JosephR
  • Start date Start date
  • Tags Tags
    Homework Matrix
JosephR
Messages
10
Reaction score
0

Homework Statement


A martix A is said to idempotent if A²=A prove the following:

a) If A is idempotent then I-A is also idempotent
b) If A is idempotent and invertible then A=I
c) If A is idempotent then I-2A is invertible.Find (I-2A)-1 in terms of A
d)Give an example of a 2x2 idempotent matrix A such that A is not the zero or the identity matrix

2. The attempt at a solution

a) A²=A then,(I-A)(I-A)=I-A ( prove it)
= I²-2A+A² and since A²=A then I-A=I-A
b) A²=A
A.A=A ~~> A-1.A.A=A-1.A ~>IA=I ~>A=I
c) I'm Stuck

d) i knew this part :P

so please any help on part c) i have an exam tomorow :)
 
Last edited:
Physics news on Phys.org
c) Just to see what happens, I multiplied I - 2A by itself, and got (I - 2A)(I - 2A) = I
d) Here's an idempotent 2 x 2 matrix:
<br /> \left[ <br /> \begin{array} {c c}<br /> 1 &amp; 1 \\<br /> 0 &amp; 0 <br /> \end{array} \right]<br />
 
THANK YOU DUDE ! u really helped me :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top