If Partial derivatives exist and are continuos then function is differentiable

rshalloo
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Homework Statement


Hi I'm just looking for a link to the proof of this theorem:
if the partial derivatives of function f exist and are continuous at a point then the function is differentiable there

Or even the name would be helpful
Its not a homework assignment per say, just something that our lecturer said mentioned in passing but never gave a proof of and I would like it just for the sake of completeness :P

Homework Equations



Well I think the Newton quotient is [ f(a+h,b+k) -(h)f(a,b+k)-(k)f(a+h,b) ]/Sqrt[h^2+k^2]
(for 2 variables anyway)

The Attempt at a Solution


I'm guessing that it involves the mean value theorem but I'm not entirely sure :S
 
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Any good Calculus text will have that proof- but I think it is too long and complicted to be given here.

(By the way, the phrase is "per se"- "of itself".)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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