I'm LOST Car is suppose to overtake truck but at what velocity?

Click For Summary

Homework Help Overview

The discussion revolves around a kinematics problem involving two cars, C and D, moving in parallel lanes. Car C starts from rest and accelerates, while Car D moves at a constant speed of 6 m/s. The objective is to determine the speed of Car C at the moment it overtakes Car D, which occurs 5 seconds after Car C begins to move.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate the motion of both cars, particularly focusing on displacement and acceleration. There is uncertainty about how to set up the equations correctly and relate them to find the speed of Car C when it overtakes Car D.

Discussion Status

Some participants have attempted to derive equations for the displacements of both cars but express confusion about the variables and the relationships between them. Guidance has been offered regarding sketching velocity-time graphs and considering the areas under these graphs to understand the displacements better. However, there is no explicit consensus on the correct approach or solution yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the extent to which they can receive direct solutions. There is an emphasis on understanding the problem setup and the relationships between the cars' motions rather than simply calculating an answer.

nabet94
Messages
9
Reaction score
0
I'm LOST! Car is suppose to overtake truck but at what velocity?

two cars C and D move in the same direction in parrallel lanes of a straight road. C starts from rest and begins to move with a constant acceleration. at that instat the C begins to move it is overtaken by D, which is moving with a constant speed of 6ms-1
!) it is given that C's acceleration remains constant the instant it overtakes D. this occurs 5seconds after c begins to move. Find C's speed at the instant when it overtakes D.
now i know i should ignore how D overtook C and i believe that i should use s=vt-1/2at^2 but i don't get a number answer its always a variable with a number please someone help me.
 
Physics news on Phys.org


Show what you have tried so far.
 


well i got s=vt-1/2at^2 for C is well s=d and t=T+2 (?) thus it would be d=v(T+2) - .5(a)(T+2)^2 and for D it would be d=6(T)-.5(a)(T)^2.
so it would be 6(T)-.5(a)(T)^2=v(T+2) - .5(a)(T+2)^2 thus i ended up with 6T-vT-2v
+2aT+2a that's it, I'm lost and I'm sure that its wrong
 


nabet94 said:

Homework Statement


two cars C and D move in the same direction in parrallel lanes of a straight road. C starts from rest and begins to move with a constant acceleration. at that instat the C begins to move it is overtaken by D, which is moving with a constant speed of 6ms-1
!) it is given that C's acceleration remains constant the instant it overtakes D. this occurs 5seconds after c begins to move. Find C's speed at the instant when it overtakes D.
now i know i should ignore how D overtook C and i believe that i should use s=vt-1/2at^2 but i don't get a number answer its always a variable with a number please someone help me


Homework Equations



s=vt-1/2at^2

First of all, write this equation for each of the cars, obtaining two equations. Notice that v is the initial velocity of the cars.

Then, you have to somehow relate the two equations. How would you do so? I have put some of the words of the problem in boldface to give you some ideas.
 


I had advised sketching the v-t graph for each car and noting that when the two cars draw level the second time, their displacements are equal. Since the displacements are the areas under the graphs this amounts to finding the areas of rectangles and triangles.

That thread has apparently vanished after comment:
nabet94 said:
yeah i know how to find the displacement and such but its just the equations of the components that give me a real hard time
... but there are no components to worry about - all the motion is in 1D.

You won't get a better method description without someone actually doing the problem for you and that is against the rules.
 
Last edited by a moderator:

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
17K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 6 ·
Replies
6
Views
16K
Replies
15
Views
3K