I'm LOST Car is suppose to overtake truck but at what velocity?

AI Thread Summary
The discussion revolves around determining the speed of car C at the moment it overtakes truck D, given that C starts from rest and accelerates while D moves at a constant speed of 6 m/s. The user struggles with applying the correct equations of motion, specifically s = vt - 1/2at^2, to derive a numerical answer. They express confusion over how to relate the equations for both cars to find their displacements and speeds at the point of overtaking. Suggestions include sketching velocity-time graphs to visualize the problem and noting that the displacements will be equal when the cars meet. The conversation emphasizes the need for clarity in setting up the equations rather than solving the problem outright.
nabet94
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I'm LOST! Car is suppose to overtake truck but at what velocity?

two cars C and D move in the same direction in parrallel lanes of a straight road. C starts from rest and begins to move with a constant acceleration. at that instat the C begins to move it is overtaken by D, which is moving with a constant speed of 6ms-1
!) it is given that C's acceleration remains constant the instant it overtakes D. this occurs 5seconds after c begins to move. Find C's speed at the instant when it overtakes D.
now i know i should ignore how D overtook C and i believe that i should use s=vt-1/2at^2 but i don't get a number answer its always a variable with a number please someone help me.
 
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Show what you have tried so far.
 


well i got s=vt-1/2at^2 for C is well s=d and t=T+2 (?) thus it would be d=v(T+2) - .5(a)(T+2)^2 and for D it would be d=6(T)-.5(a)(T)^2.
so it would be 6(T)-.5(a)(T)^2=v(T+2) - .5(a)(T+2)^2 thus i ended up with 6T-vT-2v
+2aT+2a that's it, I'm lost and I'm sure that its wrong
 


nabet94 said:

Homework Statement


two cars C and D move in the same direction in parrallel lanes of a straight road. C starts from rest and begins to move with a constant acceleration. at that instat the C begins to move it is overtaken by D, which is moving with a constant speed of 6ms-1
!) it is given that C's acceleration remains constant the instant it overtakes D. this occurs 5seconds after c begins to move. Find C's speed at the instant when it overtakes D.
now i know i should ignore how D overtook C and i believe that i should use s=vt-1/2at^2 but i don't get a number answer its always a variable with a number please someone help me


Homework Equations



s=vt-1/2at^2

First of all, write this equation for each of the cars, obtaining two equations. Notice that v is the initial velocity of the cars.

Then, you have to somehow relate the two equations. How would you do so? I have put some of the words of the problem in boldface to give you some ideas.
 


I had advised sketching the v-t graph for each car and noting that when the two cars draw level the second time, their displacements are equal. Since the displacements are the areas under the graphs this amounts to finding the areas of rectangles and triangles.

That thread has apparently vanished after comment:
nabet94 said:
yeah i know how to find the displacement and such but its just the equations of the components that give me a real hard time
... but there are no components to worry about - all the motion is in 1D.

You won't get a better method description without someone actually doing the problem for you and that is against the rules.
 
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