Implicit differentiation homework

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SUMMARY

The discussion focuses on finding the coordinates of turning points for the implicit function defined by the equation y³ + 3xy² - x³ = 3. The user successfully differentiates the equation with respect to x, resulting in dy/dx = (x² - y²)/(y² + 2xy). To identify turning points, the user recognizes that setting dy/dx to zero is essential, leading to the equation x² - y² = 0. The challenge lies in solving the system of equations formed by dy/dx = 0 and the original implicit equation.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with calculus concepts such as turning points
  • Knowledge of solving systems of equations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study methods for solving implicit equations
  • Learn about critical points and their classification in calculus
  • Explore the application of the implicit function theorem
  • Practice problems involving implicit differentiation and turning points
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Students studying calculus, particularly those focusing on implicit differentiation and turning point analysis, as well as educators looking for examples to illustrate these concepts.

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Question:

Find the co ords of the turning points of y^3 + 3xy^2 - x^3 = 3

Attempt:

(differentiate w.r.t. x)
d/dx(y^3 + 3xy^2 - x^3) = d3/dx

3y^2(dy/dx) + 3(2xy(dy/dx) + y^2) - 3x^2 = 0

(divide through by 3)

y^2(dy/dx) + 2xy(dy/dx) = x^2 - y^2

(take dy/dx as a comon factor)

dy/dx(y^2 + 2xy) = x^2 - y^2

dy/dx = (x^2 - y^2)/(y^2 + 2xy)

now to find turning points, you set dy/dx = 0
but with explicit differentiation, there's only one variable, but there's 2 here, so I am stuck :/
 
Last edited:
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"Turning points" must occur where dy/dx= 0 (though not all such points are turning points.

If dy/dx = (x^2 - y^2)/(y^2 + 2xy) and y^3 + 3xy^2 - x^3 = 3, can you solve those two equations for x and y?
 

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