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## Homework Statement

x^3+2t^2=9, 2y^3-3t^2=4, t=2

find the slope of the curve at the given value of t

## Homework Equations

## The Attempt at a Solution

i know dy/dx=(dy/dt)/(dx/dt) for parametrized curves

but how do i use implicit differentiation on parametrized curves?

i tried d/dt(2y^3-3t^2)=d/dt(4)

=6y^2*dy/dt-6t=0

=6y^2*dy/dt=6t

=dy/dt=t/y^2 ? but shouldn't dy/dt be defined in t's only? I am confused