x^3+2t^2=9, 2y^3-3t^2=4, t=2
find the slope of the curve at the given value of t
The Attempt at a Solution
i know dy/dx=(dy/dt)/(dx/dt) for parametrized curves
but how do i use implicit differentiation on parametrized curves?
i tried d/dt(2y^3-3t^2)=d/dt(4)
=dy/dt=t/y^2 ? but shouldn't dy/dt be defined in t's only? I am confused