# Improper integral convergence or divergence.

1. Feb 10, 2010

### crazy_nuttie

1. The problem statement, all variables and given/known data

Use Comparison Theorem to determine whether the integral is convergent or divergent:

integral from 0 to infinity of: arctan(x) / (2 + e^x)

Should look like this: http://bit.ly/cAhytV [Broken]

2. Relevant equations

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3. The attempt at a solution

I tried to compare this with the integral from 0 to infinity of 1/e^x, but that didnt succeed since 1/e^x converges and the given function is less than 1/e^x. I am not sure what to compare this with

Last edited by a moderator: May 4, 2017
2. Feb 10, 2010

### LCKurtz

Not sure why you chose 1/ex since $\arctan x \le \pi/2$ but not bounded by 1.

Anyway, why wouldn't you have succeeded if your integral is less than a known convergent integral? Your problem would be if your unknown integral was greater than a known convergent integral.

Last edited by a moderator: May 4, 2017