In which direction does static friction point?

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Static friction provides the centripetal force necessary for circular motion, but its role changes when a tangential force is applied. As the tangential force from the brother decreases the child's speed, static friction will adjust, potentially providing less centripetal force while also opposing the tangential force. The static friction force is equal to the net force acting on the child, which dictates the total acceleration. This total acceleration can be broken down into radial (centripetal) and tangential components. Overall, static friction plays a crucial role in maintaining the child's motion in a circular path while responding to changes in forces.
Warlic
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As I see it; static friction is what provides the centripetal force, but does it do anything else? When the brother applies tangential force, what will happen with the static friction, because I assume it will start to provide less centripetal force because the tangential speed of the child decreases - but will it then provide static friction against the brothers tangential force?
 

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Is the static force of friction equal to the net force acting on the child? If so, that force must produce the total acceleration of the child.

Think about how you can break the total acceleration into components in a useful way.
 
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TSny said:
Is the static force of friction equal to the net force acting on the child? If so, that force must produce the total acceleration of the child.

Think about how you can break the total acceleration into components in a useful way.
Does the static friction have an x-component that is the centripetal force and force in the y-direction that is the tangential force - which keeps the child moving tangentially to the circle with 0.5m in radius?
 
Warlic said:
Does the static friction have an x-component that is the centripetal force and force in the y-direction that is the tangential force - which keeps the child moving tangentially to the circle with 0.5m in radius?
Whether you call them x and y like that is up to you, but yes, the static friction must account for the net acceleration, and this will have both a radial (centripetal) and tangential component.
 
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