Indefinite Integral of 5*(sin(6x)/sin(3x)) - Help Needed

RedBarchetta
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Homework Statement


The integral of 5*(sin(6x)/sin(3x))dx

The Attempt at a Solution



I'm not quite sure what to do with this one. I moved 5 to the left of the integral, but then I'm lost. Apparently I'm rusty on these trig identities.

Could anyone help me get started? Thank you.
 
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Look up the double angle formula for sine, wikipedia is good. You should be able to simplify with the bottom some then.
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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