Induced charge in image problem

AI Thread Summary
The discussion centers on finding the induced charge density in the classic image problem. A participant expresses difficulty in using polar coordinates and questions the validity of the dipole approximation, noting that the potential does not meet the boundary condition of going to zero on the plane. Another contributor counters that the potential does indeed approach zero on the plane, emphasizing that the entire plane is an equipotential. They suggest expressing the potential as a sum of the potentials from both the point charge and its image, recommending the use of cylindrical coordinates for clarity. The conversation highlights the importance of correctly applying boundary conditions and coordinate systems in solving the problem.
Kaguro
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Homework Statement


Find induced charge density in the classic image problem.

Sorry, I uploaded my work in form of an image instead of typing.

I have tried to use polar coordinates to solve this. But i must have done something wrong. Please help me find the mistake.

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I do not believe you can use the dipole approximation here. It is valid for ##r>>d##. Your potential does not go to zero on the plane which is the boundary condition in this problem.
 
kuruman said:
I do not believe you can use the dipole approximation here. It is valid for ##r>>d##. Your potential does not go to zero on the plane which is the boundary condition in this problem.

But my potential does go to 0 on the plane as theta is 90 then and so cos theta is 0.
 
The entire plane is an equipotential therefore the expression must evaluate to zero for any value of angle ##\theta## and must also be zero at the origin. You should express the potential as the sum of the potentials from the point charge and its image. You would be wise to use cylindrical coordinates.
 
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