Inductors & AC Circuits (Homework) (RL Circuit)

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SUMMARY

The inductance in a series RL circuit with a resistance of 7.0 kΩ and a current increase to half its final value in 26 µs is calculated using the time constant equation, τ = L/R. The time constant τ is determined to be 26 µs, leading to the inductance L being approximately 0.2301 H. The calculation confirms the relationship between inductance, resistance, and time constant in RL circuits.

PREREQUISITES
  • Understanding of RL circuit theory
  • Familiarity with time constant calculations
  • Basic knowledge of Ohm's Law
  • Ability to manipulate exponential equations
NEXT STEPS
  • Study the behavior of RL circuits under different frequencies
  • Learn about the impact of inductance on circuit response times
  • Explore the use of simulation tools like LTspice for RL circuits
  • Investigate the effects of varying resistance on inductance in practical applications
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Electrical engineering students, hobbyists working with AC circuits, and anyone studying inductive components in circuit design.

harkirat2009
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Homework Statement


What is the inductance in a series RL circuit in which R = 7.0 kΩ if the current increases to one half of its final value in 26 µs?



Homework Equations



am i correct in assuming that i should be using the time constant equation: Tau=L/R


The Attempt at a Solution



if i was correct in using this equation then:
Tau = ((26E^-6)*2))*.63212
R = 7000 Ohms

Tau*R=L
L=.23009168 H
 
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[tex]e^{-t/\tau}=\frac{1}{2}[/tex] for t = 26 µs.
 
thank you for your help
 

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