Inhomogeneous Wave Eq. & Minkowski Spacetime Interval

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SUMMARY

The discussion centers on the relationship between the inhomogeneous wave equation with a constant term and the Minkowski spacetime interval. The equations presented are the inhomogeneous wave equation, represented as $$\nabla^2 u - \frac{1}{c^2} \frac{\partial^2 u}{\partial t^2} = S$$, and the Minkowski interval equation $$\sum_{i=0}^2 dx_i^2 - c^2 dt^2 = ds^2$$. The primary connection identified is the use of the same metric in both equations, as noted by the participant @haushofer. The discussion concludes that while both equations share a metric, deeper connections may not exist.

PREREQUISITES
  • Understanding of the inhomogeneous wave equation
  • Familiarity with Minkowski spacetime and its metric
  • Knowledge of tensor calculus, including raising and lowering indices
  • Basic concepts of scalar fields and the d’Alembertian operator
NEXT STEPS
  • Study the properties of the d’Alembertian operator in different contexts
  • Explore the implications of Minkowski spacetime in general relativity
  • Investigate the applications of inhomogeneous wave equations in physics
  • Learn about tensor analysis and its applications in theoretical physics
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The discussion is beneficial for physicists, mathematicians, and students studying theoretical physics, particularly those interested in wave equations and spacetime geometry.

Prez Cannady
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Answer is probably not, but is there some connection between the inhomogeneous wave equation with a constant term and the spacetime interval in Minkowski space?

$$
1) ~~ \nabla^2 u - \frac{1}{c^2} \frac{\partial^2 u}{\partial t^2} = \sum_{i=0}^2 \frac{\partial^2 u}{\partial x_i^2} - \frac{1}{c^2} \frac{\partial^2 u}{\partial t^2} = S
$$
$$
2) ~~ \sum_{i=0}^2 dx_i^2 - c^2 dt^2 = ds^2
$$
 
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The only connection I can think of, is that you use the very same metric in both equations. But I suspect you're looking for connections which aren't to be found.
 
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Tensorially, these are written as
g^{ab}\nabla_a\nabla_b u=S
g_{ab}ds^a ds^b=ds^2

Using the shorthand
\nabla^b\equiv g^{ab} \nabla_a
ds_{b}\equiv g_{ab}ds^a
known as raising and lowering indices,
we have
\nabla^b\nabla_b u=S
ds_b ds^b=ds^2

Using more index-gymnastics,
we can write
\nabla^b\nabla_b u=S
ds^b ds_b=ds^2

As @haushofer said, both equations use the same metric.
The first equation is an equality of scalar fields, the d’Alembertian of a scalar field u and a scalar field S .
The second equation is an infinitesimal scalar [at a point] using the RHS as an abbreviation of the LHS.
 
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