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ralph344
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Homework Statement
The initial electric field strength between oppositely charged parallel plates is 3.0 X 10^3 N/C, what would the electric field strength become if half of the charge were removed from each plate and the separation of the plates were changed from 12 mm to 8 mm?
Homework Equations
E= kq/r^2
k=9.0 X 10^9
The Attempt at a Solution
I used proportions.
Since the formula is E=kq/r^2, i rearranged the formula to Er^2/q = k. Since the k value is going to stay constant for both.
Er^2/q = Er^2/q
[(3.0 X 10^3)(0.012)^2]/q=[E(0.008)^2]/[0.5q]
E= 3.5 X 10^3 N/C
But the answer is 1.5 X 10^3 N/C...