Integral Calculus - Trigonometric Substitution

Myung
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Homework Statement


2
∫ dx / (x+1)√[2x(x+2)]
1

Homework Equations



Let x = tan θ if √(a^2 + x^2)
Where a = constant

The Attempt at a Solution



2
∫ dx / (x+1)√(2x)√(x+2)
1

2
1/√2 ( ∫ dx / (√x)(x+1)[√(x+2)]
1

Now make all x in terms of √x so we can apply relevant equation ( applied also to constant )

2
1/√2 ( ∫ dx / (√x)((√x)^2+1)[√(√x+2)]
1

Now before i go on I want to ask if this is possible so I can apply the rule of the tangent in substitution?
 
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how about noticing that
2x(x+2) = 2(x^2+2x) =2(x^2+2x+1-1) = 2((x+1)^2-1)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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