Integral of (1/(X^4+a^4))

  • Thread starter blueyellow
  • Start date
  • Tags
    Integral
In summary, the conversation discusses using suitable contours in the complex plane and the residue theorem to show the integration of (1/(X^4+a^4)) from +infinity to -infinity is equal to pi/((a^3)sqrt(2)). The participants suggest using a similar method used for the integral of 1/(x^2+a^2) but with 4 poles. One suggestion is to integrate around a square with corners at 0, R, iR, and R+iR and let R approach infinity. Another suggestion is to use the upper infinite semi-circle and closing the contour with a semicircle enclosing two poles.
  • #1
blueyellow
Use suitable contours in the complex plane and the residue theorem to show that (where a
is a real number):


integral from +infinity to -infinity (1/(X^4+a^4))=pi/((a^3)sqrt(2))


i hav tried to do something similar to what one would do for the integral of 1/(x^2+a^2) but it didnt work.please just help me get started on this question. ta in advance
 
Physics news on Phys.org
  • #2
I don't understand why it wouldn't work. You normally have 4 poles.
 
  • #3
integrate around a square with corners at
0,R,iR,R+iR
and let R->infinity
 
  • #4
lurflurf said:
integrate around a square with corners at
0,R,iR,R+iR
and let R->infinity

Isn't it easier to just use the upper infinite semi-circle, -infinity to +infinity along the real axis and then close the contour with a semicircle enclosing two of the functions four poles.
 
  • #5
^Some people like to do it that way, but then you have to deal with two poles instead of one. The savings would be even greater if we wanted to do 1/(x^1024+a^1024).
 

Related to Integral of (1/(X^4+a^4))

What is the integral of 1/(x^4 + a^4)?

The integral of 1/(x^4 + a^4) is (1/4a^3) * ln((x^2 + a^2)/(x^2 - a^2)) + (1/2a^3) * arctan(x/a). This can be derived using the substitution method or by using partial fractions.

Is there a simplified form for the integral of 1/(x^4 + a^4)?

Yes, the integral can be simplified to (1/2a^3) * ln((x^2 + a^2)/(x^2 - a^2)) + C, where C is the constant of integration.

What is the domain of the integral of 1/(x^4 + a^4)?

The domain of the integral is all real numbers except for x = ±a.

Can the integral of 1/(x^4 + a^4) be solved using integration by parts?

No, integration by parts cannot be used to solve this integral. Other methods such as substitution or partial fractions must be used.

How is the integral of 1/(x^4 + a^4) related to trigonometric functions?

The integral can be rewritten in terms of trigonometric functions as (1/2a^3) * ln(tan(x/a)) + C. This is because of the relation between arctan and tan functions.

Similar threads

  • Calculus and Beyond Homework Help
Replies
3
Views
878
  • Calculus and Beyond Homework Help
Replies
10
Views
498
  • Calculus and Beyond Homework Help
Replies
12
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
335
  • Calculus and Beyond Homework Help
Replies
5
Views
418
  • Calculus and Beyond Homework Help
Replies
12
Views
3K
  • Calculus and Beyond Homework Help
Replies
20
Views
493
  • Calculus and Beyond Homework Help
Replies
7
Views
730
  • Calculus and Beyond Homework Help
Replies
24
Views
2K
Replies
1
Views
633
Back
Top